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98 pts to correct answer! CALCULUS BC Trig Substitution (SEE Attached)

98 pts to correct answer! CALCULUS BC Trig Substitution (SEE Attached)-example-1
98 pts to correct answer! CALCULUS BC Trig Substitution (SEE Attached)-example-1
98 pts to correct answer! CALCULUS BC Trig Substitution (SEE Attached)-example-2

1 Answer

5 votes

Answer:

I=
\int\limits {sin^5\theta\ \, d\theta

Explanation:

substitute x=sinθ

dx=cosθdθ

the integrand becomes sin^5θcosθdθ / sqrt(1 - sin^2θ)

1-sin^2θ=cos^2θ

sqrt(1-sin^2θ)=cosθ

substitute back into the integrand

sin^5θcosθdθ/cosθ

=sin^5θdθ

ans is 5.

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