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The difference of two numbers is 29. The largest number is 3 more than twice the smallest number. What are the two numbers?

User Jegschemesch
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2 Answers

12 votes
12 votes

Answer:

x + y = 29 equation 1

Five more than means add 5+5 three times the smaller number:

3x equals the larger number: = y 3x + 5 = y equation 2

From equation 1x + y = 29subtract x from both sidesy = 29 - x

We now have two things that are both equal tothe larger number y.

They must be equal to each other.
3x + 5 = 29 - x

Add x to both sides 3x + x + 5 = 29 - x + x4x + 5 = 29

subtract 5 from both sides 4x + 5 - 5 = 29 - 54x = 24

divide both sides by 44x/4 = 24/4x = 6

We now know x = 6

We also know y=29-x y = 29 - 6y = 23

Your numbers are 6 and 23

Step-by-step explanation:

User Mikeho
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2.4k points
24 votes
24 votes

Final answer:

The two numbers in the problem are 26 and 55. The smallest number is 26, and the difference between the two numbers is 29. The largest number is 55, which is 3 more than twice the smallest number.

Step-by-step explanation:

This problem can be solved using algebra. We're given that the difference of the two numbers is 29. Let's represent the smallest number as 'x'.

The problem also mentions that the largest number is 3 more than twice the smallest number, which we can express as '2x + 3'.

Since these two numbers have a difference of 29, we can create the equation '2x + 3 - x = 29', which simplifies to 'x + 3 = 29'. Solving for 'x', we find that the smallest number is 26.

Substituting x=26 into the equation for the largest number, '2x + 3', we find that the largest number is 55. Therefore, the two numbers are 26 and 55.

Learn more about Algebraic Problem

User Jauny
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2.9k points
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