229k views
5 votes
Solve 58×29 using a area model

Solve 58×29 using a area model-example-1

2 Answers

4 votes

Hope this helps you out.

Solve 58×29 using a area model-example-1
User Sherie
by
7.6k points
4 votes

Answer:

Explanation:

From the figure attached,

Four rectangles have been formed with different dimensions.

Area of the rectangle with the dimensions = 50 unit by 20 unit

Area of the rectangle = 50×20 = 1000 unit²

Area of the rectangle with the dimensions = 8 unit by 20 unit

Area of the rectangle = 8×20 = 160 unit²

Area of the rectangle with the dimensions = 50 unit by 9 unit

Area of the rectangle = 50×9 = 450 unit²

Area of the rectangle with the dimensions = 8 unit by 9 unit

Area of the rectangle = 8×9 = 72 unit²

Total area of the big rectangle = 1000 + 160 + 450 + 72

= 1682

Therefore, 58×29 = 1682

Solve 58×29 using a area model-example-1
User Nubaslon
by
8.6k points