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5 votes
Solve for d. 4−d<4+d

User Peterhil
by
7.6k points

2 Answers

6 votes

Final answer:

To solve the inequality 4−d < 4+d, subtract 4 from both sides, add d to both sides, and divide both sides by 2 to solve for d. The solution is d > 0.

Step-by-step explanation:

To solve the inequality 4−d < 4+d, we can start by subtracting 4 from both sides of the inequality:

4−d−4 < 4+d−4

-d < d

Next, we can add d to both sides of the inequality:

-d+d < d+d

0 < 2d

Finally, we can divide both sides of the inequality by 2 to solve for d:

0/2 < 2d/2

0 < d

Therefore, the solution to the inequality is d > 0.

User Ngesh
by
8.5k points
6 votes
This is all real numbers. No matter what d is, 4-d will always be less than 4+d
User Brent Chapman
by
8.9k points

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