1 Answer

Martin Cook · Answer 1 · 2022-03-13T03:31:37+0000

Answer:

An equation of the circle with centre (5,7) and radius 2 is
$\mathbf{(x-5)^2+(x-7)^2=4}$

Option A is correct.

Explanation:

A circle in the xy-plane has centre (5,7) and radius 2. Which of the following is an equation of the circle.

The equation of circle is of form:
(x-h)^2+(x-k)^2=r^2 where (h,k) is centre and r is radius.

We have centre (5,7) so, we have h = 5 and k = 7

We have radius = 2 so, r = 2

Putting values in the equation and finding the required equation:

$(x-h)^2+(x-k)^2=r^2\\(x-5)^2+(x-7)^2=(2)^2\\(x-5)^2+(x-7)^2=4$

So, an equation of the circle with centre (5,7) and radius 2 is
$\mathbf{(x-5)^2+(x-7)^2=4}$

Option A is correct.

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