Answer:
x ≥ -6
Explanation:
Please use parentheses around the argument (input) of the sqrt function:
Better: sqrt( 1/3x + 2)
Much better: sqrt ( (1/3)x + 2)
The input to the sqrt function must be 0 or greater. Thus, we must solve the equation (1/3)x + 2 ≥ 0. Mult. all 3 terms by 3, we get x + 6 ≥ 0, or x ≥ -6.