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Write the equation of the line for the following table of values.

x. -3 -5 -7 -9 -11


y. -16 -26 -36 -46 -56


Plz helppp 35 points:)​

1 Answer

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Answer:

We conclude that the equation of the line is:


  • y = 5x + 1

Explanation:

The slope-intercept form of the line equation


y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the data table

x -3 -5 -7 -9 -11

y -16 -26 -36 -46 -56

From the table taking two points

  • (-3, -16)
  • (-5, -26)

Determining the slope between (-3, -16) and (-5, -26)


\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)


\left(x_1,\:y_1\right)=\left(-3,\:-16\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-26\right)


m=(-26-\left(-16\right))/(-5-\left(-3\right))


m=5

Thus, the slope of the line is: m = 5

substituting m = 5 and (-3, -16) in the slope-intercept form of the line equation to determine the y-intercept b


y = mx+b

-16 = 5(-3) + b

-16 = -15 + b

b = -16+15

b = 1

Thus, the y-intercept b = 1

now substituting m = 5 and b = 1 in the slope-intercept form of the line equation


y = mx+b


y = 5x + 1

Therefore, we conclude that the equation of the line is:


  • y = 5x + 1
User Olaj
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