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A fictitious element Q has two naturally occurring isotopes. The first isotope has an abundance of 10.00% and a mass of 39.06 amu and the second isotope of element Q has an abundance of 90.00% and a mass of 42.14 Amy. Calculate the weighted atomic mass of element Q to the nearest tenth. Show work

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Given, mass of isotope 1 = 39.06 amu

% abundance of isotope 1 = 10.00%

mass of isotope 2 = 42.14 amu

% abundance of isotope 2 = 90.00%

Average atomic mass

= [ (mass of isotope 1 x % abundance of isotope 1 ) + (mass of isotope 2 x % abundance of isotope 2 ) ]/ 100

= [(39.06 x 10) + (42.14 x 90)]/100

= (390.6 + 3792.6) / 100

= 4183.2/100

= 41.8 (to the nearest tenth)

Therefore, the weighted atomic mass of element Q is 41.8 amu.

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