Question

three players scored a total of 70 points during a basketball game one player scored twice as many as one mate and 10 points fewer than the other teammate. how many points did each player score

Answer 1

40+20+10=70
40 is twice 20
10 is 10 fewer than 20.

Answer 2

24, 12 and 34.

Explanation:

Let points of all three players are
`x_1,\ x_2,\ x_3` respectively.

It is given that sum of their score is 70.

Therefore,
`x_1+x_2+x_3=70`. ...1

Also, score of one is twice the other.

So,
`x_1=2x_2`. ...2

It is also given that its score is 10 points less than the other one.

Therefore,
`x_1=x_3-10` ...3

Solving all three equations we get,

`x_1=24, \ x_2=12,\ x_3=34`.

Hence,it is the required solution.