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PLEASE HELP WITH TWO MATH QUESTIONS!!!!

1. Complete the following proof

Given: –x – 4 = 9
Prove: x = –13

Statements Reason
1. –x – 4 = 9 1. Given
2. –x = 13 2.
3. x = –13 3. Division Property of Equality

Choices: Addition Property of Equality, Subtraction Property of Equality, Multiplication Property of Equality, or Division Property of Equality
2. Complete the proof.

Given: AB = 7x + 1, BC = 4x, AC = 111
Prove: x = 10

Statement Reason
1. AB = 7x + 1, BC = 4x, AC = 111 1. Given
2. AC = AB + BC 2.
3. 111 = 7x + 1 + 4x 3.
4. 111 = 11x + 1 4. Combine Like Terms
5. 110 = 11x 5. Subtraction Property of Equality
6. 10 = x 6. Division Property of Equality
7. x = 10 7.
Choices for 2, 3, and 7: Picture Below.

User Terez
by
6.2k points

2 Answers

6 votes

Answer:

Part A.

Given: –x – 4 = 9

Prove: x = –13

-x - 4 = 9 - Given

-x = 13 - Addition Property of Equality

or

x = -13 - Division of Equality

Part B.

Given: AB = 7x + 1, BC = 4x, AC = 111

Prove: x = 10

AB = 7x + 1, BC = 4x, AC = 111 - Given


AC=AB+BC- This step is Segment Addition Postulate


111=7x +1+4x - This is also Segment Addition Postulate


111 = 11x+1 - Now we will combine like terms


110=11x - Subtraction Property of Equality


10 = x - Here we will apply division Property of Equality


x = 10 - Symmetric Property of Equality

User Tom Lehman
by
5.8k points
0 votes

Answer => Explanation:

Given: -x - 4 = 9

Prove: x = -13

-x - 4 = 9 ; Given

-x = 13 ; Addition Property of Equality

You isolate the x by adding 4 to both sides ; of the equal sign)

x = -13 ; Division of Equality

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Answer => Step-by-step explanation:

Given: AB = 7x + 1, BC = 4x, AC = 111

Prove: x = 10

Statement Reason

AB = 7x + 1, BC = 4x, AC = 111 ; Given

AC = AB + BC ; Segment Addition Postulate

111 = 7x + 1 + 4x ; Segment Addition Postulate

111 = 11x + 1 ; Combine like terms

110 = 11x ; Subtraction Property of Equality

10 = x ; Division Property of Equality

x = 10 ; Symmetric Property of Equality

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~

User Nikos
by
5.9k points