Question

How Would You Solve (2x+1)(x-5)

Answer 1

The answers are x = -.5 and x = 5

Explanation:

Typically when asked to solve quadratics like this, we are looking for when the equation equals 0. In order to find when the equation is equal to 0, we need to find when each parenthesis is equal to 0.

2x + 1 = 0

2x = -1

x = -.5

x - 5 = 0

x = 5

Answer 2

2x^2 - 9x - 5

Explanation:

This is a multiplication problem; it's not an equation and thus can't be "solved." Rather: "Multiply out (2x+1)(x-5)."

(2x+1)(x-5) = 2x^2 - 10x + x - 5, or 2x^2 - 9x - 5. This is the "product" of (2x+1)(x-5).