Given : AB = 44 + 3x
BC = 33 + x
CD = 64 − x
AD = 48 − 2x.
Opposite sides are AB and CD.
BC and AD.
Setting AB equals CD
We get
44 + 3x = 64 − x
Adding x on both sides, we get
44 + 3x+x = 64 − x+x
44 +4x = 64.
Subtracting 44 from both sides, we get
44-44 +4x = 64 - 44.
4x =20
Dividing both sides by 4, we get
x= 5.
Let us plug x=5 to find the length of each side, we get
AB = 44 + 3x = 44 +3(5) = 44 + 15 = 59 cm
BC = 33 + x = 33 + 5 = 38 cm
CD = 64 − x = 64 - 5 = 59 cm
AD = 48 − 2x = 48 - 2(5) = 48 - 10 = 38 cm.
We can see that AB = CD = 59 cm and BC = AD = 38 cm.
Therefore, quadrilateral ABCD is a parallelogram.