What is the equation of the parabola with focus (1, -3) and directrix y = 2? OA. y=-3x²+2x-2 OB. y=-4x²+8x-21 OC. Y=2/3x^2-4/3x+7/6. OD. Y=-1/10x^2+1/5x-3/5

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Demitrius Nelon asked Feb 8, 2023

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What is the equation of the parabola with focus (1, -3) and directrix y = 2?

OA. y=-3x²+2x-2
OB. y=-4x²+8x-21
OC. Y=2/3x^2-4/3x+7/6. OD. Y=-1/10x^2+1/5x-3/5

Mathematics
high-school

Demitrius Nelon asked Feb 8, 2023

by Demitrius Nelon

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Answer:

y = -x^2/10 + x/5 - 3/5

Explanation:

The answer is D: just rearrange

Zuljin answered Feb 13, 2023

by Zuljin

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