Question

During takeoff, a plane accelerates at 4 m/s and takes 40 s to reach takeoff speed. What is the velocity of the plane at takeoff?

Answer 1

To find the plane's takeoff velocity with an acceleration of 4 m/s² and a duration of 40 seconds, use the formula v = u + at. Since the plane starts from rest (u = 0), the final velocity (v) will be 160 m/s.

Step-by-step explanation:

To calculate the velocity of the plane at takeoff when it accelerates at 4 m/s2 for 40 seconds, you can use the equation of motion:

v = u + at

Where:

• v is the final velocity,
• u is the initial velocity (which is 0 since the plane starts from rest),
• a is the acceleration,
• t is the time.

Substituting the given values:

v = 0 + (4 m/s2 × 40 s)

v = 160 m/s

Therefore, the velocity of the plane at takeoff is 160 meters per second.

Answer 2

Velocity = distance / time

v = d /t

= 4ms⁻¹ / 40s

v = 0.4 ms⁻² .