AC = CB, hence ΔABC is isosceles
the base angles 34 and x - 5 are therefore equal
x - 5 = 34 ( add 5 to both sides )
x = 39
and 4y = 180 - ( 2 × 34 ) = 112
4y = 112 ⇒ y = 28
Answer:
x=39° ,y=28°
Explanation:
In the given figure
Side AC = Side BC
Hence ΔABC is an isosceles triangle.
⇒∠CAB =∠CBA (∵ angles opposite to equal sides are equal)
⇒ (x - 5)° = 34°
⇒ x = 39
Also in Δ ABC
∠ABC + ∠ACB + ∠CAB = 180°
(∵ Sum of all the interior angles of a triangle)
⇒ 34° + 34° + 4 y = 180°
⇒ 4 y =180°-68°
⇒ y=112°÷ 4
⇒y= 28°
Hence, x = 39° , y = 28°
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