Given equation :

Adding 24 on both sides, we get


Let us factor this.
5*24 = 120.
b=-34.
So, we need to find the factors of 120 that add upto -34.
-30 and -4 are the factors add upto -34 and product 120.






Setting each factor equal to 0 and solve for x.
x-6 =0
x=6.
5x-4 =0.
5x = 4.
x=4/5.
Therefore, final answer is x=6, 4/5.