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Jika garis 4x+ay = 8 dan ay=9x + 5 saling tegak lurus,maka nilai a

User Krsna
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1 Answer

4 votes

We are given equations as


4x+ay=8

Firstly, we will write in slope intercept form of line

y=mx+b


4x+ay=8

Subtract both sides by 4x


4x+ay-4x=-4x+8


ay=-4x+8

now, we can divide both sides by a


y=-(4)/(a) x+(8)/(a)

we can find slope

so, we get


m_1=-(4)/(a)

we are given second equation as


ay=9x+5

Firstly, we will write in slope intercept form of line

y=mx+b

divide both sides by a


y=(9)/(a) +(5)/(a)

we can find slope


m_2=(9)/(a)

we are given both lines are perpendicular

so, the multiplication of their slopes must be -1


m_1* m_2=-1

we can plug values


-(4)/(a)* (9)/(a)=-1

now, we can solve for a


(36)/(a^2)=-1

Multiply both sides by a


(36)/(a^2)* a^2=1* a^2


36= a^2

now, we can solve for a

we get


a=-6,a=6...............Answer

User Perdomoff
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