1 Answer

Hashim MH · Answer 1 · 2019-02-15T15:38:27+0000

mass of the chair = 25 kg

Force required to start the motion = 165 N

Force required to maintain the motion = 127 N

part a)

when we applied the force to just start the motion then it is just equal to the limiting friction force

F_s = F

now as we know that

$\mu_s mg = 165$

$\mu_s * 25 * 9.8 = 165$

$\mu_s = (165)/(25*9.8)$

$\mu_s = 0.67$

PART b)

when object has started motion then to maintain its motion we need external force to balance kinetic friction

F_k = F

now as we know that

$\mu_k mg = 127$

$\mu_k * 25 * 9.8 = 127$

$\mu_k = (127)/(25*9.8)$

$\mu_k = 0.52$

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