Question

A compound of two chemicals is mixed in a ratio of 3:12 if there are 45L of the compound how much of each chemical is in the mixture

Answer 1

We need 9L from one chemical and 12L from the other.

Explanation:

What 3:12 means is that if you add 3L from one chemical(lets say A chemical) then you will have to add 12L from the other chemical (lets say B chemical) to make the compound.

Now Lets take that you added
`x`L of chemical A to make 45L of the compound.

So if add 3L from chemical A you have to add 12L of chemical B, so if you add
`x`L of A then how many liters of B do you need?

⇒
`(12)/(3) *x`

=
`4x`

So you will need
`4x`L of chemical B.

Now we can write an equation for the total amount of compound B as,

⇒
`x+4x=45`

`5x=45`

`x=9`

Therefore,

We need 9L of chemical A, and

We need 36L of chemical B

Answer 2

3x+12x=45

15x=45

x=3

the first chemical is 3*3 or 9 L

the second chemical is 12*3 = 36 L