Question

A triangle's perimeter is x2-3x+10. Side 1 is -8x+5 and side 2 is 3x+3. What is the third side?

Answer 1

p = s1 +s2+s3

x^2-3x+10 = -8x+5 +3x+3 +s3

combine like terms

x^2 -3x+10 = 5x+8 +s3

subtract (5x+8) from each side

x^2 -8x +2 =s3

The third sdie is x^2 -8x+2