(11)
the equation of a line in point- slope form is
y = mx + c ( m is the slope and c the y-intercept
thus y = 4x + 3 ← in slope-intercept form
the equation of a line in point- slope form is
y - b = m(x - a ) ( m is slope and (a, b ) a point on the line )
thus y - 3 = 4 ( x - 0 ) or y - 3 = 4x ← in point- slope form
the equation of a line in standard form is
Ax + By = C ( a is a positive integer and B, C are integers
rearrange y - 3 = 4x into this form
4x - y = - 3 ← in standard form
(12)
y = - 2x - 1 ← in slope-intercept form
y + 1 = - 2x ← in point- slope form
2x + y = - 1 ← in standard form