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A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20 degrees. What os the maximum height reached by the squirrel.

User KernelM
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2 Answers

2 votes

Answer:

0.3 m

Step-by-step explanation:

I used the formula for range which is:
R = (v^2)/(g) * sin(2*theta)

v = 7, theta = 20, g = 9.8 so I just plugged it in and solved

User AdamOutler
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5 votes


Given:\\v_0=7(m)/(s)\\\alpha =20^\circ\\g=10(m)/(s^2) \\\Find:\\H=?\\\\Solution:\\\\ H=(v^2_0\sin^2\alpha)/(2g) \\\\H=((7(m)/(s))^2\cdot (\sin(20^\circ))^2)/(2\cdot 10(m)/(s^2)) \approx 0.3m\\\\\\Proof\;that\;H=(v^2_0\sin^2\alpha)/(2g)\;in \;appendage

A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20 degrees. What-example-1
User Therightstuff
by
8.4k points
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