Question

Suppose that a laser light, positioned 100 ft from the base of a flag pole, illuminates a flag that is 85 ft above the ground.

What is the angle of inclination (angle of elevation) of the light beam?

Answer 1

The angle of inclination (angle of elevation) of the light beam is 40.364...°

Explanation:

According to the below diagram,
`A` is the position of the flag which is 85 ft above the ground. That means,
`AB= 85` ft.

`C` is the position of laser light, which is 100 ft from the base of the flag pole. That means,
`BC= 100` ft.

Suppose, the angle of inclination of the light beam is
`\theta` degree.

Now in
`\triangle ABC`, we will get........

`tan(\theta)= (AB)/(BC) \\ \\ tan(\theta)=(85)/(100)=0.85 \\ \\ \theta=tan^-^1(0.85)=40.364...`

So, the angle of inclination (angle of elevation) of the light beam is 40.364...°