Question

Solve for X.
5+4/7(21+ 3X)= 41

Answer 1

5+4/7(21+ 3X)= 41

-5

4/7(21+3x)=36

*7/4

21+3x=63

-21

3x=42

/3

x=14

Answer 2

Consider the equation
`5+(4)/(7)\left(21+3x\right)=41.`

1. Multiply this equation by 7:

`5\cdot 7+(4)/(7)\cdot 7 (21+3x)=41\cdot 7,\\\\35+4(21+3x)=287.`

2. Eliminate brackets:

`35+4\cdot 21+4\cdot 3x=287,\\\\35+84+12x=287.`

3. Separate terms with x into the left side and without x into the right side:

`12x=287-35-84,\\\\12x=168.`

4. Find x:

`x=168:12,\\ \\x=14.`

Answer: x=14.