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To solve the system of equations below grace isolated the variable y in the first equation and then substituted it in the second equation. What was the resulting equation?

To solve the system of equations below grace isolated the variable y in the first-example-1

1 Answer

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Answer:

The correct option will be:
(x^2)/(25)- (4x^2)/(49)=1

Explanation:

The system of equations is...........


4y=8x ............................(1)\\ \\ (x^2)/(25)- (y^2)/(49)=1 ........................(2)

Grace isolated the variable y in the first equation. So, she divided equation (1) by 4 in both sides. That means.......


(4y)/(4)= (8x)/(4) \\ \\ y=2x

Then she substituted this
y=2x into equation (2).

So, the resulting equation will be......


(x^2)/(25)- ((2x)^2)/(49)=1 \\ \\ (x^2)/(25)- (4x^2)/(49)=1

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