67.7k views
5 votes
I need help!!!

Select the correct answer.
Sean has a rectangular painting with an area of 80 square inches. He wants to enlarge the painting to 320 square inches.
If the length and width of the original painting are 10 inches and 8 inches, what will the dimensions of the enlarged painting be?
A.
12 inches and 10 inches
B.
14 inches and 12 inches
C.
20 inches and 16 inches
D.
40 inches and 32 inches

2 Answers

4 votes

Answer:

THE ANSWER ISSS OPTION C

Explanation:

I GOT IT RIGHT ON EDMENTUM HOPE THIS HELPS YOU OUT ALOT ;0

User SaroGFX
by
6.5k points
3 votes

Answer: OPTION C.

Explanation:

1. By defintion the scale factor of the area is
k^(2) and this is:


k^(2)=(A_1)/(A_2)=(320)/(80)=4

2. Then, the scale factor for the sides is:


k=√(4)=2

3. Now, you must multiply the length and the width of the original rectangle by 2 to obtain the new dimensions. Thefore, you obtain:


l=10in*2=20in\\w=8in*2=16in

Therefore, the answer is the option C.

User Shrikant K
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.