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What are the solutions of 2x^2-6x+5=0

User Dannypaz
by
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2 Answers

4 votes

Answer: x=3+i/2 or x=3-i/2

APEX

User Jens Borrisholt
by
7.9k points
1 vote

x =
(3)/(2) ±
(1)/(2)i

the equation has no real zeros but instead has 2 complex zeros

the discriminant = b² - 4ac

with a = 2, b= - 6, c = 5

b² - 4ac = (-6)² - (4 × 2 × 5 ) = -4

since b² - 4ac < 0 there are no real zeros

using the quadratic formula

x = ( 6 ± √(- 4 ) )/4 = ( 6 ± 2i ) / 4

x =
(6)/(4) ±
(2)/(4) i

=
(3)/(2) ±
(1)/(2) i

User Desenfoque
by
7.7k points

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