x =
±
i
the equation has no real zeros but instead has 2 complex zeros
the discriminant = b² - 4ac
with a = 2, b= - 6, c = 5
b² - 4ac = (-6)² - (4 × 2 × 5 ) = -4
since b² - 4ac < 0 there are no real zeros
using the quadratic formula
x = ( 6 ± √(- 4 ) )/4 = ( 6 ± 2i ) / 4
x =
±
i
=
±
i