Answer:
No.
Step-by-step explanation:
The freezing process is not an exception, simply because the pan of liquid water cannot be considered an isolated system.
In fact, the law of entropy holds for isolated systems only: the entropy of an isolated system can never decrease. However, in this case the pan of liquid water is not an isolated system, since it exchanges energy with the surrounding. In particular, it gives thermal energy away to the environment, so its temperature decreases and it freezes: the entropy of the pan of water decreases, but the total entropy of the system (pan of water + environment) does not decrease.