Question

Which expression is equivalent to 2/7k(k-7)? Assume k=0.A. 2/7-k,B. 2/7-2/k,C. 2k/7-7,D. 2k/7k-2k

Answer 1

`(2)/(7k)(k-7)\qquad|\text{use distributive property}\\\\=\left((2)/(7k)\right)(k)-\left((2)/(7k)\right)(7)=(2)/(7)-(2)/(k)`

Answer 2

ANSWER

B.

`(2)/(7k) (k - 7) = (2)/(7)- (2)/(k)`



Step-by-step explanation

The given expression is


`(2)/(7k) (k - 7)`
where k≠0

We expand the bracket to get,



`(2)/(7k) (k - 7) = (2)/(7k) * k - (2)/(7k) * 7`



We now cancel out the common factors to obtain,



`(2)/(7k) (k - 7) = (2)/(7) * 1- (2)/(k) * 1`



We now simplify to obtain,


`(2)/(7k) (k - 7) = (2)/(7)- (2)/(k)`


The correct answer is option B.