Question

Marcus tosses a coin and spins a spinner numbered from 1 to 3. What is the probability the coin lands heads up and the spinner lands on 1?

Answer 1

1/6

Explanation:

Answer 2

Answer:
`(1)/(6)`

Explanation:

Given statement : Marcus tosses a coin and spins a spinner numbered from 1 to 3.

Let A be the event of getting a head while tossing a coin.

Total faces on coin=2

Then
`P(A)=(1)/(2)`

Let B be the event of spinner lands on 1.

Total sections on spinner = 3

Then
`P(B)=(1)/(3)`

Since both events are independent of each other.

Therefore, the probability the coin lands heads up and the spinner lands on 1 =
`P(A)*P(B)=(1)/(2)*(1)/(3)=(1)/(6)`

Hence, the probability the coin lands heads up and the spinner lands on 1 =
`(1)/(6)`