Answer:
The shortest distance between checkpoint A and checkpoint B is 23.33 yards.
Explanation:
We are given the following information in the question:
Let O be the starting point.
Distance between the starting point and checkpoint A = 20 yards
To reach checkpoint B, one need to take a turn and let it be a 90 degrees turn toward right or left.
Distance between checkpoint A and checkpoint B = 12 yards
In order to find the shortest distance between the checkpoint A and checkpoint B, the displacement, we use the Pythagoras theorem.
Statement:
In a right angled triangle:
![(Side 1)^2 + (Side 2)^2 = (Hypotenuse)^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/k5t540c04l5uarruhv5taecg61ztlu0nbd.png)
![(OA)^2 + (AB)^2 = (AB)^2\\(20)^2 + (12)^2 = (AB)^2\\400 + 144 = (AB)^2\\(AB)^2 = 544\\AB = √(544) \approx 23.33](https://img.qammunity.org/2019/formulas/mathematics/middle-school/244z5aez2dt2i583vo61g0buu23j6kkqqs.png)
Hence, the shortest distance between checkpoint A and checkpoint B is 23.33 yards.