Question

Help me please! I'm stuck and I need the answer now! Thx so much!

Answer 1

If ,

`\bold{z=-3+5i }`

so,conjugate of z

`\overline{ z }`=
`\bold{-3-5i }`

Because, in argand plane
`\overline{ z }` is the reflection of z in x-axis.

so,

According to the question,

z
`\overline{z}`=(-3+5i)(-3-5i)

`\bold{(-3)^2-(5i)^2 }`

`\bold{9-25(-1) }`

`\bold{ 9+25 }`

`\bold{ 34 }`

Answer 2

• 34

Explanation:

Given

• z = -3 + 5i

Conjugate of z is:

• z' = -3 - 5i

Product zz' is:

• zz' = (-3 + 5i)(-3 - 5i) = (-3)² - (5i)² = 9 - 25(-1) = 9 + 25 = 34