Final answer:
The student's question involves solving a system of two linear equations using the elimination method. By transforming the equations to have the same coefficient for y, adding them, and then solving for x and y, the student will find the specific values that solve both equations simultaneously.
Step-by-step explanation:
The student has presented two linear equations that need to be solved simultaneously:
To solve this system of equations, we can use either the substitution method, the elimination method, or matrix methods. Let's solve it using the elimination method:
- First, multiply the first equation by 3 and the second equation by 4 to make the coefficients of y the same: 3(y - 4x) = 3·3 and 4(2x - 3y) = 4·21.
- The transformed equations are 3y - 12x = 9 and 8x - 12y = 84.
- Add the first transformed equation to the second to eliminate y: -12x + 8x - 12y + 3y = 9 + 84.
- Simplify to find the value of x: -4x - 9y = 93. Now solve for x.
- Substitute the value of x back into one of the original equations to find the value of y.
Once we have the values for x and y, we have the solution to the system of equations.