89.1k views
5 votes
Y-4x=3. 2x-3y=21 can someone help

2 Answers

4 votes

Final answer:

The student's question involves solving a system of two linear equations using the elimination method. By transforming the equations to have the same coefficient for y, adding them, and then solving for x and y, the student will find the specific values that solve both equations simultaneously.

Step-by-step explanation:

The student has presented two linear equations that need to be solved simultaneously:

  • y - 4x = 3
  • 2x - 3y = 21

To solve this system of equations, we can use either the substitution method, the elimination method, or matrix methods. Let's solve it using the elimination method:

  1. First, multiply the first equation by 3 and the second equation by 4 to make the coefficients of y the same: 3(y - 4x) = 3·3 and 4(2x - 3y) = 4·21.
  2. The transformed equations are 3y - 12x = 9 and 8x - 12y = 84.
  3. Add the first transformed equation to the second to eliminate y: -12x + 8x - 12y + 3y = 9 + 84.
  4. Simplify to find the value of x: -4x - 9y = 93. Now solve for x.
  5. Substitute the value of x back into one of the original equations to find the value of y.

Once we have the values for x and y, we have the solution to the system of equations.

User Chameera Ashanth
by
7.8k points
1 vote

Y-4X =3 ; 2x-3y=21

Y= 3+ 4x

2x -3( 3+4x)= 21

2x- 9- 12x= 21

-10x -9= 21

-10x -9+9= 21+9

-10x = 30

X= 30/-10= -3

Y= 3+4x = 3+ 4* (-3)= 3-12= -9

User ShrimpCrackers
by
7.1k points