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What is the equation of a line that is parallel to 2x +3y = 3 and passes through the point (3, -4) ?

User Isklenar
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1 Answer

7 votes

Answer:

2x + 3y = -6

Explanation:

The equation of the new line will be identical to that of the given line except that the constant term will differ.

Start with the given 2x + 3y = 3 and replace x with 3 and y with -4. We get:

2(3) + 3(-4) = C, and C = 6 - 12 = -6

The equation of the new line is therefore 2x + 3y = -6

User Shangari C
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