Question

Mason is preparing for an endurance running competition. On Friday, he ran 15 3/5 miles. On Saturday, he ran twice as much as he did on Friday. On Sunday, he ran 3 3/4 less than he did on Saturday. How many miles did Mason run for three days?

Answer 1

he ran for 34 and 19/20 miles

Answer 2

`74 (5)/(20)`

Explanation:

On Friday, he ran
`15(3)/(5)` miles.

converting mix number to fraction we get,

`15(3)/(5)` =
`(75+3)/(5)` =
`(78)/(5)`

On Saturday, he ran twice as much as he did on Friday.

so, for Saturday it is,

2 x
`(78)/(5)` miles

=
`(78 x 2)/(5)`

=
`(156)/(5)`

On Sunday he ran
`3(3)/(4)` less than Saturday.

`3(3)/(4)`=
`(12+3)/(4)` =
`(15)/(4)`

So, for Sunday it is-

`(156)/(5)` -
`(15)/(4)`

=
`(156x4-15x5)/(20)`

=
`(624-75)/(20)`

=
`(549)/(20)`

So, for three days,

total distance would be-

`(78)/(5)` +
`(156)/(5)` +
`(549)/(20)`

=
`(78x4 + 156x4 + 549)/(20)`

=
`(312+624+549)/(20)`

=
`(1485)/(20)`

=
`74 (5)/(20)`

So, Mason ran
`74 (5)/(20)` miles in three days.