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What is the product? (5r+2)(3r-4)

2 Answers

4 votes

First distribute 5r to the 3r and -4 to get 15r^2-20r

Second distribute 2 towards 3r and -4 to get 6r-8

Aftr your whole eqausion should look like

15r^2-20r+6r-8

Since 15r^2 cant be added to anything leave it as is and the rest of the equation should be this

15r^2-14r-8

It should be easy to figure out from there

User Dipo
by
7.5k points
3 votes

Answer:

15r^2 − 14r − 8

User Marcus Grass
by
7.9k points

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