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A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?

User Surita
by
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1 Answer

7 votes

Answer:

12 in wide by 16 in high

Explanation:

Let w represent the width of the enlarged picture. Then the height is (4/3)w, and the area is the product of width and height:

... area = width × height

... 192 in² = w × (4/3)w . . . . substitute the given information

... 192 in² = (4/3)w² . . . . . . . simplify

... 144 in² = w² . . . . . . . . . . . multiply by 3/4

... 12 in = w . . . . . . . . . . . . . .take the square root

... height = (4/3)w = (4/3)(12 in) = 16 in

User Lee Ballard
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