Solve the inequality 3y <= 2y + 3

Question

asked Nov 4, 2019 135k views

1 Answer

Hotzst · Answer 1 · 2019-11-09T04:49:34+0000

Answer:

$y\leq 3$

All real numbers less than or equal to 3

Explanation:

we have

$3y\leq 2y+3$

Solve for y

Subtract 2y both sides

$3y-2y\leq 2y+3-2y$

$y\leq 3$

The solution is the interval ------> (-∞,3]

All real numbers less than or equal to 3

In a number line the solution is the shaded area down of y=3 (close circle)

see the attached figure