Question

A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy

Answer 1

`9\:\mathrm{J}`

Step-by-step explanation:

Kinetic energy is given by the following equation:

`KE=(1)/(2)mv^2`, where
`m` is mass in
`\mathrm{kg}` and
`v` is velocity in
`\mathrm{m/s}`.

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

`80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}`.

Therefore, the kinetic energy of the cell phone is:

`KE=(1)/(2)\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}`.