Question

A motorcycle slows down uniformly from a speed of 21 m/s to rest in 6.0s. How far did it travel during this time?

Answer 1

63 m

Step-by-step explanation:

The initial velocity of the motorcycle is

`v_i = 21 m/s`

The final velocity is

`v_f = 0`

And the time taken is

`t=6.0 s`

Since the acceleration of the motorcycle is uniform, we can find the distance traveled by the motorcycle during this time by using the following SUVAT equation:

`S=(1)/(2) (v_i +v_f) t`

Substituting numbers into the equation, we find

`S=(1)/(2)( 21 m/s + 0)(6.0 s)=63 m`