Question

What is the equilibrium constant expression for the given system? CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

Answer 1

• Kc = [CH3OH] ÷ [CO][H2]∧2

Step-by-step explanation:

CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

• Rate of forward reaction = Kf [CO][H2]∧2
• Rate of reverse reaction = Kr [CH3OH]

At equlibrium

Rate of forward = rate of reverse

Kf [CO][H2]∧2 = Kr [CH3OH]

Kf/Kr = [CH3OH] ÷ [CO][H2]∧2

Kc = [CH3OH] ÷ [CO][H2]∧2