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Park rangers released 4 fish into the pond in year 0. Each year, there were three times as many fish as the year before. How many fish were there after x years ? Write a function to represent this senario

User Ponkin
by
6.7k points

2 Answers

3 votes

Answer:

f(x) = 4(3)^x

Explanation:

User Harjeet Jadeja
by
7.3k points
7 votes

Answer:


y = 4(3)^x.

Explanation:

Year 0 = 4 fishes

Since we are given that Each year, there were three times as many fish as the year before.

So , Year 1 =
3 * 4 = 12 dishes

Year 2 =
3 * 12 = 36 fishes

And so on

So, we can use formula of exponential growth :
y = ab^x

where y is the number of fishes after x years

a is the initial amount

b is the growth factor

x is the number of years

a = 4

b = 3

Substitute the values in the formula :


y = 4(3)^x

To Check substitute x = 0


y = 4(3)^0


y = 4

Park rangers released 4 fish into the pond in year 0

To Check substitute x = 1


y = 4(3)^1


y = 12

Park rangers released 12 fish into the pond in year 1

Hence verified

Hence a function to represent this senario is
y = 4(3)^x.

User Suchi
by
6.4k points