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Limit of cot2x/cotx as X approaches 0?

User Jad
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1 Answer

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Use the l'Hopital's rule, two times.


\lim_(x\rightarrow0) (\cot(2x))/(\cot(x))=\lim_(x\rightarrow0) (2\sin^2(x))/(\sin(x))=\lim_(x\rightarrow0) (4(\cos^2(x)-\sin^2(x)))/(8(\cos^2(2x)-sin^2(2x))) = (1)/(2)

let me know if you have questions

User Ata
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