Question

Please help me with this problem (:

Answer 1

`f(x) = -2( x - 3) + 5, x \leq 3\\\\g(x) = 2(x-3)+5, x > 3`

Explanation:

turning pt of the abs fn |x-3| is at x=3

`2|x-3|=-2(x-3), x\leq 3\\\\2|x-3|=2(x-3), x>3`

so

`f(x) = -2( x - 3) + 5, x \leq 3\\\\g(x) = 2(x-3)+5, x > 3`

Answer 2

f(x)=-2*(x-3)+5 when x<3

g(x)=x(x-3)+5 when x>3

Explanation:

| | is absolute function meaning the value must be larger than or equal to zero.

So | x-3 | = -(x-3) when x<3

f(x)=-2*(x-3)+5 when x<3

| x-3 | = (x-3) when x>3

g(x)=2*(x-3)+5 when x>3