Question

1.Ms. Bowery bought five shirts and one pair of pants for a total of $56.23. Each shirt cost

the same price. The pants cost $7 more than a shirt. How much did each shirt cost? Round to
the nearest dollar and cent
A) $9.20
B) $49.26
C) $8.20
D) $10.20

Answer 1

I believe it’s C. Because $8.20x5 is 41, then 8.50+7= $15.50 so then add 41+15.50= 56.50. That’s just my guess.

Answer 2

`\mathrm{C)\:} \$8.20`

Explanation:

Let
`s` represent the cost of each shirt in dollars. We can write the cost of the pants as
`s+7`. Using these terms, set up the following equation:

`5s+(s+7)=56.23`.

Solving, we get:

`5s+s+7=56.23,\\6s=56.23,\\6s=49.23\\s\approx \fbox{$\$8.20$}`