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Find the cube root of 1/27

User Szydlovski
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1/3is the answer to this

User KaseOga
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\bf \sqrt[3]{\cfrac{1}{27}}~~\begin{cases}1^3=1\\27=3^3\end{cases}\implies \sqrt[3]{\cfrac{1^3}{3^3}}\implies \cfrac{\sqrt[3]{1^3}}{\sqrt[3]{3^3}}\implies \cfrac{1}{3}

User Ian Emnace
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