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Hi · Answer 1 · 2019-07-18T23:58:02+0000

use the pythagorean theorem

${a}^(2) + {b}^(2) = {c}^(2)$
input your values

${20}^(2) + {21}^(2) = {c}^(2)$
solve

${20}^(2) + {21}^(2) = 41 {}^(2)$
then square root 'c'

$√(41) = 6.4 \: or \: √(41)$
these options are for if your teacher wants it in radical form as mine had

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