For this case we have the following equation, in a linear way:
![y + 2 = 3 (x-1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/gyecg0x4rwys3k4204323yfb19qmlblgia.png)
This expression can be written in the form
![y = mx + b](https://img.qammunity.org/2019/formulas/mathematics/high-school/i6zw0h9pe9ud2am0fso5etqxn9ng1dt2x4.png)
Where "m" is the slope and "b" is the cut point with the y axis.
Rewriting the given expression we have:
![y + 2 = 3x-3\\y = 3x-3-2\\y = 3x-5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mao0p9gl04nwpha0m05v1tmbeu74vku6xv.png)
Thus, the slope is 3 and the cut point is -5.
To graph, we must find two points through which the line passes, so, we perform the following steps:
Step 1:
We do
![x = 0](https://img.qammunity.org/2019/formulas/mathematics/high-school/wws4ks1ut5eylfw6x6dakxv11dvibpmdxr.png)
![y = 3 (0) -5\\y = 0-5\\y = -5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/s3gjdzjemwzd8cpo3d3bjori4kfwrmwfv6.png)
Thus, the point
![(x1, y1) = (0, -5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mgy813b1th44zt3hn3jltl0paq0it9nico.png)
Step 2:
We do
![y = 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/o5mg4xdeeegllzd1h3cxx9dym7pw8i37gc.png)
![0 = 3x-5\\5 = 3x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/4x5lfmpukmbto66fm1sfqspgyy6wt06mng.png)
![x =(5)/(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/icvrpcd16gp9icgyj6fqqxvru9hpfke0g8.png)
Thus, the point
![(x2, y2) = ((5)/(3),0)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/up5nr6bzx93vazshbdmk5tdsrtug9pgil7.png)
Answer:
See attached image