Question

G(n-7) if g(x) =x^2-5/3x

Answer 1

Instead of x, we write n - 7 in the function equation

`g(x)=x^2-(5)/(3)x\\\\g(n-7)=(n-7)^2-(5)/(3)(n-7)\\\\\text{use} (a-b)^2=a^2-2ab+b^2\\\text{and distributive property}\\\\=n^2-2(n)(7)+7^2+\left(-(5)/(3)\right)(n)+\left(-(5)/(3)\right)(-7)\\\\=n^2-14n+49-(5)/(3)n+(35)/(3)\\\\\text{combine like terms}\\\\=n^2+\left(-14n-1(2)/(3)n\right)+\left(49+11(2)/(3)\right)\\\\=n^2-15(2)/(3)n+60(2)/(3)`