Question

FIND THE SLOPE OF THE LINE WITH THE FOLLOWING POINTS

(3, 6) AND (0, 4)

WRITE AN EQUATION USING POINT SLOPE FORM WITH A SLOPE OF 2.6 AND CROSSES THE POINT (-5.1, 3.8)

Answer 1

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have (3, 6) and (0, 4)

Substitute:

`m=(4-6)/(0-3)=(-2)/(-3)=(2)/(3)`

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The slope-point formula:

`y-y_1=m(x-x_1)`

We have:

m = 2.6 and (-5.1, 3.8)

Substitute:

`y-3.8=2.6(x-(-5.1))\\\\y-3.8=2.6(x+5.1)`